Re: [Haskell-beginners] pattern matching on a common element

You still can! Using Rahul's solution, that is. On Thu, Nov 24, 2016 at 11:08 PM, wrote:

On Fri, 25 Nov 2016 12:06:06 +0530 Rahul Muttineni wrote:

...

data X = A1 { name :: String, d :: Double} | A2 { name :: String, i :: Int} | A3 { name :: String, d1 :: Double, i1 :: Int}

Now you can use `name` directly to get the string component of the different variants.

Hope that helps!

oops, i forgot to mention.

i'd like to be able to write my code;

x = [ A1 "a1" 2.0, A2 "a2" 3 ]

etc... to save myself a lot of typing.

_______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners

-- Jeff Brown | Jeffrey Benjamin Brown Website https://msu.edu/~brown202/ | Facebook https://www.facebook.com/mejeff.younotjeff | LinkedIn https://www.linkedin.com/in/jeffreybenjaminbrown(I often miss messages here) | Github https://github.com/jeffreybenjaminbrown