Re: [Haskell-beginners] Why can't I print an IO Integer?

20 Oct 2015

      Hello,

Function "print" has type "Show a => a -> IO ()". To use it with a value of
type "IO Int", you need to use (>>=), which, specialized to IO, has type
"IO a -> (a -> IO b) -> IO b". "print =<< foo", if foo :: IO Int, will have
type IO () and is going to print the integer from foo. In your code,
though, you can use mapM instead of map:

    sizes <- mapM get_size filenames
    mapM_ print sizes

Best regards,
Marcin Mrotek