Re: [Haskell-beginners] function defenition. Do I understand it right?

You are missing a parenthesis in your otherwise alternative, right before the where. There are a few other problems including, you are using single quotes ' instead of back quotes ` for your mod functions, and you don't have commas in between the elements of your pairs. Despite that the algorithm needs a bit more work to do what you want, but you are close: http://codepad.org/9pA4cLwb On Mon, Jul 11, 2011 at 5:13 PM, Roelof Wobben wrote:

Hello,

I had a look at it but I don't think it will solve my problem.

What I try to achieve is this:

[1,2,3,4] will be [1,2] [3,4]

[1,2,3,4,5] will be [1,2,3] [3,4,5]

So the halfs have to be the same lenght.

So I use :

length xs'div' 2 to figure out where the middle is.

lenght xs'mod'2 to look if it's a even or not even list.

So I can use splitat but then the lists will not be the same length if it's a not even list.

Roelof

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Subject: Re: [Haskell-beginners] function defenition. Do I understand it right? From: jhenahan@uvm.edu Date: Mon, 11 Jul 2011 15:55:13 -0400 To: rwobben@hotmail.com

You're overcomplicating things. Look at splitAt from Data.List:

http://hackage.haskell.org/packages/archive/base/4.1.0.0/doc/html/Data-List....

On Jul 11, 2011, at 3:51 PM, Roelof Wobben wrote:

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Hello,

Thanks for the tip. Im stuck now.

I have this :

halve (xs) | length xs'mod'2 == 0 = (take n xs drop n xs) | otherwise = (take n+1 xs drop n+1 xs where n= lenght xs'div'2

main = do putStrLn $ show $ halve [1,2,3,4] putStrLn $ show $ halve [1,2,3]

But now I get this message :

ERROR line 3 - Syntax error in expression (unexpected keyword "where")

Appearently I can't use where here.

How can I solve this ?

Roelof

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Date: Mon, 11 Jul 2011 11:44:28 -0400 Subject: Re: [Haskell-beginners] function defenition. Do I understand it right? From: dmcbride@neondsl.com To: rwobben@hotmail.com CC: beginners@haskell.org

For simple snippets like this, you can go to http://codepad.org/ddySVOPr and run your code to see if it works.

And your first version (once corrected for syntax) works on any list length except for empty lists.

On Mon, Jul 11, 2011 at 10:48 AM, Roelof Wobben wrote:

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Hello,

I have made a exercise where I must split a even list. The answer is :

halve xs = (take n xs drop n xs) where n = length xs 'div' 2

Now I want to change it so i can split even and not even list,. I thought this can be the answer

halve xs = lenght xs 'mod' 2 = 0 : (take n xs drop n xs) otherwise : (take n+1 xs drop n+1 xs) where n = length xs 'div' 2

Can this be working ? I did not check this on GCHI because Im re - installing my OS.

Regards.

Roelof

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