5 Aug
2010
5 Aug
'10
11:34 p.m.
On Thu, 5 Aug 2010 19:07:13 -0700
prad
correcting it by sticking on a delimiter doesn't seem to be the right thing to do though. so there must be another way to deal with this. hmmm.
i think i can solve the dilemma by introducing an accessory function getTail: br [] = [] br ss = fst (tup) : br (getTail (snd tup)) where tup = break eqD ss getTail s | s==[] = [] | otherwise = tail s it works, though i don't know if this is necessarily the best way to do it. -- In friendship, prad ... with you on your journey Towards Freedom http://www.towardsfreedom.com (website) Information, Inspiration, Imagination - truly a site for soaring I's