Re: [Haskell-beginners] IO action on a list of [IO a]

6 Oct 2012


      On Sat, 06 Oct 2012 16:16:18 +0200, Manfred Lotz   
wrote:
...
myfor :: (a -> IO () ) -> [IO a] -> IO ()
myfor _ [] = return ()
myfor f (x:xs) = do
  x' <- x
  f x'
  myfor f xs
Is there a library function doing just this?
You could use this:
   import Control.Monad
   myfor :: (a -> IO () ) -> [IO a] -> IO ()
   myfor f (x:xs) = mapM_ (liftM f) xs

or this:
   import Data.Functor
   myfor :: (a -> IO () ) -> [IO a] -> IO ()
   myfor f (x:xs) = mapM_ (f <$>) xs

For a description of liftM see:
   http://members.chello.nl/hjgtuyl/tourdemonad.html#liftM

Regards,
Henk-Jan van Tuyl


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