On Sun, 25 Jul 2010 00:15:24 +0200
Daniel Fischer
Maybe this helps:
foldr op z [x1, x2, x3] = x1 `op` (x2 `op` (x3 `op` z))
foldr1 op [x1, x2, x3] = x1 `op` (x2 `op` x3)
thx daniel. the above seems to be the idea of replacing (:) with the function as illustrated in the Another approach on the wiki: http://www.haskell.org/haskellwiki/Fold possibly, i'm making too big a deal trying to say it all in words. i understand what it is doing and how to use it (for the most part) as well as the 'Another approach' illustration. possibly i should just stick to that. -- In friendship, prad ... with you on your journey Towards Freedom http://www.towardsfreedom.com (website) Information, Inspiration, Imagination - truly a site for soaring I's