Re: [Haskell-beginners] pattern matching on a common element

On Fri, 25 Nov 2016 12:06:06 +0530 Rahul Muttineni wrote:

data X = A1 { name :: String, d :: Double} | A2 { name :: String, i :: Int} | A3 { name :: String, d1 :: Double, i1 :: Int}

Now you can use `name` directly to get the string component of the different variants.

Hope that helps!

oops, i forgot to mention. i'd like to be able to write my code; x = [ A1 "a1" 2.0, A2 "a2" 3 ] etc... to save myself a lot of typing.