Re: [Haskell-beginners] Trying to understand the foldl type?

Given foldl (+) 0 [1..10] (+) is (a -> b -> a) 0 is a [1..10] is [b] and the final a is the result of the expression. On Tuesday, December 24, 2013, Angus Comber wrote:

The type is:

foldl :: (a -> b -> a) -> a -> [b] -> a

Eg I might do something like this:

foldl (+) 0 [1..10]

so taking (a -> b -> a)

leftmost a is (+) b is 0 right a is what? The first value in the list?

Then -> ?

[b] ? Is this like the temporary recursion calculation?

final -> a is the result?