Re: [Haskell-beginners] applicative default structure

So normally it should fail but the default typing in ghci is the one who makes our life easier. Thanks for the explanation! On Thu, Dec 22, 2016 at 5:33 PM, David McBride wrote:

Rather than bailing with an instance error for both Applicative and Num, which is the technically the right way, and the way that it used to be in the dark ages of ghci. Instead it chooses types which are probably what you wanted. In this case it defaults f to IO and a to Int, and then runs it.

You can read more about type defaulting in ghci here: https://downloads.haskell.org/~ghc/latest/docs/html/users_guide/ghci.html

On Thu, Dec 22, 2016 at 10:18 AM, Ovidiu Deac wrote:

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My understanding is that x can take any form required for type-inference. That's fine but what is the "default" structure if you don't specify any?

On Thu, Dec 22, 2016 at 5:13 PM, Imants Cekusins wrote:

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What is f here?

anything Applicative:

Prelude> let a1 = pure 1 Prelude> let a2 = pure 1

Prelude> (a1::Maybe Int) == a2 True Prelude> (a1::Maybe Float) == a2 True Prelude> (a1::Either String Float) == a2 True

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