Re: [Haskell-beginners] foldr point free notation

Hi Alexander, I found this tool online[1], that converts your function to a point free style. myAny'' f = foldr (\a b -> f a || b) False is transformed to myAny'' = flip foldr False . ((||) .) Again as Bob mentions, the point free style comes at a cost of unreadability and hence unmaintainable. Cheers! Apoorv [1]: http://pointfree.io/ http://pointfree.io/

On Jun 10, 2020, at 10:00, Bob Ippolito wrote:

The better question is why would you want to? If you could even manage, the result would be practically incomprehensible.

On Wed, Jun 10, 2020 at 07:49 Alexander Chen mailto:alexander@chenjia.nl> wrote: hi,

--any function foldr myAny'' :: (a-> Bool) -> [a] -> Bool myAny'' f = foldr (\a b -> f a || b) False

this is the foldr notions. How would i make this point free?

best, _______________________________________________ Beginners mailing list Beginners@haskell.org mailto:Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners