Re: [Haskell-beginners] applicative instance

Ok so how would the implementation look to get the correct result ? I can't seem to write something that will compile except ZipList version. Thanks, Sasa

On Jan 27, 2017, at 23:21, Francesco Ariis wrote:

On Fri, Jan 27, 2017 at 11:09:07PM +0100, sasa bogicevic wrote:

...

What is wrong with my applicative instance for custom List type ?

http://lpaste.net/351723

[..]

You have implemented <*> on a list in one of the many possible (and sensible) ways. In regular Haskell it's a ZipList

λ> :m Control.Applicative λ> ZipList [(+1), (*2)] <*> ZipList [1,2] ZipList {getZipList = [2,4]}

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