12 Feb
2010
12 Feb
'10
9:30 a.m.
The reason I wanted to use Data.Tree instead of my own is that I hoped to serliaze it using Data.Binary (which supposed to support Data.Tree) Alas, It doesn't work. Need to figure it out yet.. *Main Data.Binary Data.Tree> :m +Data.Binary *Main Data.Binary Data.Tree> encode aTree <interactive>:1:0: No instance for (Binary ANode) arising from a use of `encode' at <interactive>:1:0-11 Possible fix: add an instance declaration for (Binary ANode) In the expression: encode aTree In the definition of `it': it = encode aTree -- Regards, Gabi http://bugspy.net