Re: [Haskell-beginners] Is there an "unscan" function?

2012/1/12 Kyle Murphy :

I was able to build something incredibly convoluted that accomplishes what you want, but I'm sure there's a better way to do it.

Not sure if it's a better way. unscan l = head l : zipWith (subtract) l (tail l) Corrected to work for empty lists : unscan [] = [] unscan l@(x:xs) = x : zipWith (subtract) l xs David.