Hello
If you have a list of String for each record, use partition from
Data.List, e.g.:
import Data.List ( partition )
partitionBySize :: [[String]] -> ([[String]],[[String]])
partitionBySize = partition (\xs -> length xs < 10)
-- for demo-ing:
printShortsLongs :: ([[String]],[[String]]) -> IO ()
printShortsLongs (xs,ys) = do
putStrLn "Shorts:"
mapM_ print xs
putStrLn "Longs:"
mapM_ print ys
demo1 = printShortsLongs $ partitionBySize [
["1", "2", "3", "4", "5", "6", "7", "8", "9", "10" ]
, ["1", "2", "3", "4"]
, ["1", "2", "3", "4", "5", "6", "7", "8", "9", "10" ]
, ["1", "2", "3", "4", "5", "6", "7", "8", "9", "10" ]
, ["1", "2", "3", "4"]
]
On 9 February 2010 10:53,
Hi, i get a .csv file with two different record formats (too bad). The first one, identified by a "A" in the second field, contains 4 fields. The second one, identified by a "B", contains 10 fields.
In order to put them in lists, i use lines then break to get a list of lists. Then i want to filter this list, one for the A list, the other one for the B list. Unfortunately, the pattern for the A type contains 4 fields; when a type B list occurs (10 fields), i get a message concerning the pattern : Non-exhaustive patterns in lambda
How can i separate the two record formats?
Thanks, Didier _______________________________________________ Beginners mailing list Beginners@haskell.org http://www.haskell.org/mailman/listinfo/beginners