
10 Aug
2011
10 Aug
'11
2:20 p.m.
To require an Integer implies you have a list of 2 billion+ elements
and that's pretty huge for a list. Take is used a lot, and using an
Int instead of Integer for something that gets called so often is just
common sense.
On Wed, Aug 10, 2011 at 10:14 AM, Sunil S Nandihalli
Hi everybody, I feel forcing the first argument of take to be an Int is unnecessarily restrictive .. Is there a rationale behind not making it just (Integral a) ? right now it is take::Int->[a]->[a] I was thinking may be take::(Integral b)=>b->[a]->[a] would be better... Thanks, Sunil. _______________________________________________ Beginners mailing list Beginners@haskell.org http://www.haskell.org/mailman/listinfo/beginners