Re: [Haskell-beginners] Mutable variables in do block?

Hi, On 24 February 2013 10:41, Emanuel Koczwara wrote:

it appears that the first and second 'line' are just an ordinary immutable variables. Line 4 just hides the 'line' from line 2 (outer lambda). Am I right?

Exactly. You can try desugaring the do notation to see what's going on even more clearly. Best, Ozgur