Re: [Haskell-beginners] pattern matching on a common element

data X = A1 { name :: String, d :: Double} | A2 { name :: String, i :: Int} | A3 { name :: String, d1 :: Double, i1 :: Int} Now you can use `name` directly to get the string component of the different variants. Hope that helps! Rahul On Fri, Nov 25, 2016 at 11:16 AM, <briand@aracnet.com> wrote:

Here's what I'm doing:

data X = A1 String Double | A2 String Int | A3 String Double Int

name c = case c of A1 name _ -> name A2 name _ -> name A3 name _ _ -> name

I'm sure there's a better way... _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners

-- Rahul Muttineni