Re: [Haskell-beginners] Why is it so slow to solve "10^(10^10)"?

On Sun, Sep 22, 2013 at 12:50 AM, Graham Gill wrote:

10^(10^10) is a 1 followed by ten billion zeros. Naively evaluating that to an integer is going to cause time and memory problems in any software that supports arbitrary size integers - as Bob Ippolito said, it's

I wonder if they were looking for (**) instead of (^). -- brandon s allbery kf8nh sine nomine associates allbery.b@gmail.com ballbery@sinenomine.net unix, openafs, kerberos, infrastructure, xmonad http://sinenomine.net