Hello, Kwangrae. I think the following function will work for you: multSM :: Double -> Matrix -> Matrix --multiplies a scalar and a matrix multSM d m = [ [d * b | b <- a] | a <- m] I just use nested list comprehension. 2010/2/2 조광래 :

hi I have a question about haskell coding.

Matrices

One of many ways to define matrices in Haskell is the list of matrix rows, where a row is a list of double precision oating point numbers:

type Matrix=[[Double]]

Using this type you should define the following functions (definition of dim is given as an inspirational example).

dim :: Matrix -> (Int,Int) --returns matrix dimension (number of rows and columns) dim m = if (not.isMatrix) m then error "Not a matrix" else (length m, length (head m))

isMatrix :: Matrix -> Bool --checks whether all rows have the same length isMatrix m = and [length (head m) == length a | a <- m]

I have done upto here and I am stuck on multSM.

multSM :: Double -> Matrix -> Matrix --multiplies a scalar and a matrix

when I do:

multSM d m = [[(b*a)| b<-[d], a<-(head m)]] or [map (*d) (head m)]

...I get (using Hugs):

Main> multSM 3 [[2,3,4],[1,3,4],[6,3,0]] [[6.0,9.0,12.0]]

So I solve 3 [2,3,4] but I do not know how to get the rest 3 [[1,3,4],[6,3,0].

Please help me on this problem.

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