Awesome, I clearly am off on my understanding. How could I do this: "foldl (+) 0 estimates <+> (Just . fromIntegral) (length estimates)" without the parenthesis? Thanks, Wes
The actual code I have working is:
let estimates = [5,5,8,8,2,1,5,2]
(/) <$> (Just $ foldl (+) 0 estimates) <*> ((Just . fromIntegral) (length estimates))
What I want to do is get rid of all the parentheses except (/)
Is it possible?
Thanks,
wes
From: Beginners
On Fri, Aug 28, 2015 at 2:51 PM, Williams, Wes(AWF)
What I want to do is get rid of all the parentheses except (/) Is it possible?
Not without breaking it up into chunks like you did in ghci (probably using a let or where). -- brandon s allbery kf8nh sine nomine associates allbery.b@gmail.com ballbery@sinenomine.net unix, openafs, kerberos, infrastructure, xmonad http://sinenomine.net
Thanks for the feedback and guidance Brandon!
From: Beginners
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Brandon Allbery -
Williams, Wes(AWF)