
have some code that works but want to put it in a simple function without sucess: getBD :: Connection -> String -> Float getBD conn name = noBDfp where qry_head = "select `N° BD` from sidonie.Coordonnées where Nom = ?" :: Query bd_rows = do local_bd_rows <- query conn qry_head (Only (name::String)) return local_bd_rows i want the variable local_bd_rows accessible in the 'where' clause how can i do that? note the goal is to do the same thing of my main function that works : main :: IO () --main :: Int main = do conn <- connect defaultConnectInfo { connectHost = "moita", connectUser = "mattei", connectPassword = "******", connectDatabase = "sidonie" } -- we get all the Double Stars that have angular distance superior to a threshold of 1 second = 0.000278 degree rows <- query_ conn "SELECT Nom,distance FROM AngularDistance WHERE distance > 0.000278" forM_ rows $ \(name,distance) -> putStrLn $ Text.unpack name ++ " " ++ show (distance :: Double) -- we will get the Durchmusterung Number BD from Sidonie and WDS and compare them for a given name -- Warning: there could be multiple result in WDS for a given entry name (due to components) -- first we get the N°BD from sidonie let name = "A 20" -- let qry = "select `N° BD` from Coordonnées where Nom = " ++ name let qry_head = "select `N° BD` from sidonie.Coordonnées where Nom = ?" :: Query -- bd_rows <- query_ conn "select `N° BD` from sidonie.Coordonnées where Nom = 'A 20'" bd_rows <- query conn qry_head (Only (name::String)) putStrLn $ show bd_rows putStrLn $ show name let resLst = Prelude.map fromOnly bd_rows let noBDtxt = fromOnly (Prelude.head bd_rows) :: Text -- let noBD2 = _ (Prelude.head bd_rows) putStrLn $ show resLst putStrLn $ show noBDtxt forM_ bd_rows $ \(Only a) -> putStrLn $ Text.unpack a let noBDstr = Text.unpack noBDtxt :: String let noBDfp = read $ noBDstr :: Float putStr "noBDfp =" (putStrLn (show noBDfp)) close conn print "Exit." for now i have errors in the function: Prelude> :load UpdateSidonie [1 of 1] Compiling Main ( UpdateSidonie.hs, interpreted ) UpdateSidonie.hs:47:28: error: • Ambiguous type variable ‘r0’ arising from a use of ‘query’ prevents the constraint ‘(QueryResults r0)’ from being solved. Relevant bindings include bd_rows :: IO [r0] (bound at UpdateSidonie.hs:46:9) Probable fix: use a type annotation to specify what ‘r0’ should be. These potential instances exist: instance Result a => QueryResults (Only a) -- Defined in ‘Database.MySQL.Simple.QueryResults’ instance (Result a, Result b) => QueryResults (a, b) -- Defined in ‘Database.MySQL.Simple.QueryResults’ instance (Result a, Result b, Result c) => QueryResults (a, b, c) -- Defined in ‘Database.MySQL.Simple.QueryResults’ ...plus 21 others (use -fprint-potential-instances to see them all) • In a stmt of a 'do' block: local_bd_rows <- query conn qry_head (Only (name :: String)) In the expression: do local_bd_rows <- query conn qry_head (Only (name :: String)) return local_bd_rows In an equation for ‘bd_rows’: bd_rows = do local_bd_rows <- query conn qry_head (Only (name :: String)) return local_bd_rows | 47 | local_bd_rows <- query conn qry_head (Only (name::String)) | ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ Failed, no modules loaded. -- Damien.Mattei@unice.fr, Damien.Mattei@oca.eu, UNS / OCA / CNRS

Hy Damien, On Mon, Dec 10, 2018 at 11:32:23AM +0100, Damien Mattei wrote:
i want the variable local_bd_rows accessible in the 'where' clause
does `query` return IO ()? If so, no you can't*. Once the result is inside IO, it stays in IO. Move what you need inside out of where (and inside a `do`) and get ready to change the signature of `getBD` to getBD :: Connection -> String -> IO Float -F * (you can with unsafeSomething functions, but it is really really advisable not to do that).

query returns a list i suppose because i can wirte this in my main code: bd_rows <- query conn qry_head (Only (name::String)) putStrLn $ show bd_rows putStrLn $ show name let resLst = Prelude.map fromOnly bd_rows i can o a map on bd_rows i just want to convert this code in Main: let qry_head = "select `N° BD` from sidonie.Coordonnées where Nom = ?" :: Query -- bd_rows <- query_ conn "select `N° BD` from sidonie.Coordonnées where Nom = 'A 20'" bd_rows <- query conn qry_head (Only (name::String)) putStrLn $ show bd_rows putStrLn $ show name let resLst = Prelude.map fromOnly bd_rows let noBDtxt = fromOnly (Prelude.head bd_rows) :: Text -- let noBD2 = _ (Prelude.head bd_rows) putStrLn $ show resLst putStrLn $ show noBDtxt forM_ bd_rows $ \(Only a) -> putStrLn $ Text.unpack a let noBDstr = Text.unpack noBDtxt :: String let noBDfp = read $ noBDstr :: Float where i succeed in putting the Float extracted and converted from the result of query in a variable of type Float, i want to have this in function getBD that take as arguments the Connection and the String name ,i use name in the SQL query and get back the noBD in text first ,string and finally float... this should be done,i assume it is possible in haskell but i'm a beginner.... i have problem finding good doc ,understanding Monads ans '<-' use and 'do' but i assume the solution is perhaps trivial... Le 10/12/2018 12:19, Francesco Ariis a écrit :
Hy Damien,
On Mon, Dec 10, 2018 at 11:32:23AM +0100, Damien Mattei wrote:
i want the variable local_bd_rows accessible in the 'where' clause
does `query` return IO ()? If so, no you can't*. Once the result is inside IO, it stays in IO. Move what you need inside out of where (and inside a `do`) and get ready to change the signature of `getBD` to
getBD :: Connection -> String -> IO Float
-F
* (you can with unsafeSomething functions, but it is really really advisable not to do that). _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners
-- Damien.Mattei@unice.fr, Damien.Mattei@oca.eu, UNS / OCA / CNRS

On Mon, Dec 10, 2018 at 03:46:46PM +0100, Damien Mattei wrote:
query returns a list i suppose because i can wirte this in my main code: bd_rows <- query conn qry_head (Only (name::String))
`query` does not return a `[r]`, rather an `IO [r]`. The difference is very important; if you don't get it you will always have troubles with Haskell. This will for sure help you https://www.seas.upenn.edu/~cis194/fall16/lectures/06-io-and-monads.html

thank you, i understand the difference, but can not see a solution, seems i need main :: IO so keep code in main, which is not really a problem, but i wanted to structure it more... i will keep searching a solution, understanding more haskell Le 10/12/2018 16:06, Francesco Ariis a écrit :
On Mon, Dec 10, 2018 at 03:46:46PM +0100, Damien Mattei wrote:
query returns a list i suppose because i can wirte this in my main code: bd_rows <- query conn qry_head (Only (name::String))
`query` does not return a `[r]`, rather an `IO [r]`. The difference is very important; if you don't get it you will always have troubles with Haskell. This will for sure help you
https://www.seas.upenn.edu/~cis194/fall16/lectures/06-io-and-monads.html _______________________________________________ Beginners mailing list Beginners@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/beginners
-- Damien.Mattei@unice.fr, Damien.Mattei@oca.eu, UNS / OCA / CNRS
participants (2)
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Damien Mattei
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Francesco Ariis