This works myAvg :: [Float] -> Float myAvg [] = 0.0 myAvg xs = (foldr (+) 0.0 xs) / (fromIntegral (length xs) :: Float) but is there a simpler way to "cast" the value of (length xs)? On Fri, Feb 5, 2021 at 12:29 PM Ut Primum wrote:

Hi, when you write 3 Haskell sees it as a "num" while the type of the length [1,2,3] is "int". So 3 and length [1,2,3] have not the same type.

Il ven 5 feb 2021, 19:23 Lawrence Bottorff ha scritto:

...

I can divide a float by an integer

...

2.4 / 3 0.7999999999999999

but why can I not do this?

< 2.4 / (length [1,2,3]) <interactive>:288:1-22: error: * No instance for (Fractional Int) arising from a use of `/' * In the expression: 2.4 / (length [1, 2, 3])

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