I was wondering whether it was possible using fixed-vector, ut dependent types seem to be a new thing I can experiment with. Thanks for the quick reply. On 12 March 2015 at 03:26, Adam Bergmark <adam@bergmark.nl> wrote:

If I understand you correctly you seem to want dependent types, this article uses the same example you need, promoting the length of a vector/list to the type level: https://www.fpcomplete.com/user/konn/prove-your-haskell-for-great-safety/dep...

You'd end up with `plot :: (Vector n Double -> Double) -> Vector n (Double, Double) -> IO ()' where `n' is the length of the vector.

HTH, Adam

On Wed, Mar 11, 2015 at 10:45 PM, Sumit Sahrawat, Maths & Computing, IIT (BHU) <sumit.sahrawat.apm13@iitbhu.ac.in> wrote:

...

Hi everybody,

I have a function of type

plot :: ([Double] -> Double) -- A function to plot -> [(Double, Double)] -- Range for all arguments -> IO ()

I want to enforce the fact that ranges for all arguments should be provided. Is there a way to make the type system enforce it?

-- Regards

Sumit Sahrawat

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-- Regards Sumit Sahrawat