Sorry, I misunderstood your ruby. The Day datatype has an ordinal instance for this purpose and also a convenient show instance in case you wanted it. import Data.Time.Calendar import Data.Time.Format import System.Locale main = let (Just now) = (parseTime defaultTimeLocale "%F" "2011-07-11" :: Maybe Day) (Just end) = (parseTime defaultTimeLocale "%F" "2011-07-15" :: Maybe Day) in mapM_ print [now..end] On Sat, Jul 9, 2011 at 1:14 PM, David McBride wrote:

import Data.Time.LocalTime import Data.Time.Format import System.Locale

now :: Maybe LocalTime -- Change this to get different types of values (days, etc). now = parseTime defaultTimeLocale "%F" "2011-07-11"

main = putStrLn $ case now of                    Nothing -> "Failed Parse"                    Just x -> (formatTime defaultTimeLocale "%F" x)

On Sat, Jul 9, 2011 at 12:33 PM, Rolf Hanson wrote:

...

Hi, I'm trying to iterate over a range of dates and print them out. Here's how I am doing it in Ruby:

'require 'date'

now      = Date.parse('2011-07-11') end_date = Date.parse('2011-12-31')

(now..end_date).each do |d|  # print out a date that looks like:  # Monday, July 11, 2011  puts "#{d.strftime('%A, %B %d, %Y')}" end

I've been looking at the docs for Data.Time.Format and Data.Time.Calendar and am a bit puzzled at where to begin. Anyone have ideas? I've not found many (any?) examples of time and date manipulation in Haskell.

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