
Yikes, I was afraid of reaching for something like DataIfStar. But I
don't have any other ideas, so let's play along with that example.
Frustratingly, I can't even write the class definition of DataIfStar.
If I do, GHC yells at me like so:
• Expected a type, but ‘k’ has kind ‘t’
• In the first argument of ‘Data’, namely ‘k’
In the type signature:
dataIf :: (t ~ Type) => proxy k -> (Data k => r) -> r -> r
In the class declaration for ‘DataIfStar’
In other words, GHC isn't smart enough to see that in the (Data k =>
r) argument, k's kind t should be the same as *. This is pretty
annoying, because this overlapping instances trick only works due to
the fact that their instance heads distinguish between kinds. In other
words, if you were to change the definition of DataIfStar to this:
class Typeable k => DataIfStar (k :: *) where
dataIf :: proxy k -> (Data k => r) -> r -> r
Then although the class declaration would now typecheck, the two
instances below it would be flagged as duplicate instances because
they now have the same instance head! Ugh.
Somehow, I need to be able to defer an equality constraint at the type
level, but just writing (t ~ Type) => ... doesn't quite work,
unfortunately.
Ryan S.
On Fri, Feb 24, 2017 at 12:14 AM, Edward Kmett
That is a right mess.
I've now stepped a bit outside of what I think is a practical recommendation, but let's just keep playing for the fun of it.
This is going to be hard to do without access to GHC at the moment but here goes:
If phantom was of kind * then dataCast1 would need the (Data phantom), so we need some sort of way to supply it.
Looks like we'd need some 'Data if *'. We don't have exponentials in the type checker though. They are admissable, just not a thing GHC does today. We could fake it with some nastiness perhaps:
class (Typeable t, Typeable k) => DataIfStar (k :: t) where dataIf :: (t ~ Type) => proxy k -> (Data k => r) -> r
You might be able to make a couple of overlapping instances, as much as it pains me to consider. (Here be dragons, I haven't thought this through.
instance Data k => DataIfStar k where -- overlapping dataIf _ r = r
instance DataIfStar k where -- overlapped dataIf _ _ = undefined
Then after you check k ~ Type in the instance you could invoke dataIf using the knowledge that k ~ Type to pull the Data phantom instance into scope. You'd get a type signature like:
dataCast1T :: forall k c t (phantom :: k). (Typeable t, DataIfStar phantom) => (forall d. Data d => c (t d)) -> Maybe (c (T phantom))
which would mean the Data instance for T phantom would get a constraint like:
instance DataIfStar phantom => Data (T phantom)
Does that make sense?
-Edward
On Thu, Feb 23, 2017 at 10:30 PM, Ryan Scott
wrote: Supplying the default shouldn't lock our data instance to the form T a. If for some reason adding this default would break the instance We can make a more interesting default that does something like look at the kind of the argument first to determine if it is kind * before proceeding after casting to ensure the kinds match.
Interesting. Do you happen to know how to write this "more interesting default"? I've tried various things, but sadly I can't escape past the typechecker. My attempt that made it the furthest was this:
{-# LANGUAGE GADTs #-} {-# LANGUAGE PolyKinds #-} {-# LANGUAGE RankNTypes #-} {-# LANGUAGE ScopedTypeVariables #-} {-# LANGUAGE TypeInType #-} {-# LANGUAGE TypeOperators #-} module DataCast where
import Data.Data import Data.Kind (Type)
data T (phantom :: k) = T
dataCast1T :: forall k c t (phantom :: k). (Typeable k, Typeable t, Typeable phantom) => (forall d. Data d => c (t d)) -> Maybe (c (T phantom)) dataCast1T f = case eqT :: Maybe (k :~: Type) of Nothing -> Nothing Just Refl -> gcast1 f
This would work were it not for the constraints involved:
Could not deduce (Data phantom) arising from a use of ‘f’
It seems that applying f is forcing the type parameter to T (phantom) to be a Data instance, which obviously can't happen if (phantom :: k). I don't know a way around this, though, as I'm not aware of a way to "defer" a class constraint (unlike equality constraints, which can be deferred via Typeable).
Ryan S.
On Thu, Feb 23, 2017 at 5:49 PM, Edward Kmett
wrote: Some thoughts on the topic: admittedly, probably not very useful.
A couple of obvious statements:
1)
gcast1 itself operationally makes sense regardless of the kind of the argument you're skipping past.
gcast1 :: forall c t t' a. (Typeable t, Typeable t') => c (t a) -> Maybe (c (t' a))
This is an operation we can define pretty easily, however we want. It works more or less by definition. It was included in the original paper.
2)
dataCast1 on the other hand is an member of the class, and it needs that 'Data d' constraint or it can't do its job.
dataCast1 :: (Data a, Typeable t) => (forall d. Data d => c (t d)) -> Maybe (c a)
Attempting to weaken the Data d constraint there doesn't work, because then dataCast1 wouldn't be able to do its job. Without it you can't write ext1Q in terms of dataCast1, as noted in the but about 'bogusDataCast' in the original paper: Scrap More Boilerplate: Reflection, Zips and Generalized Casts
Since then we obviously picked up polymorphic kinds, which muddled the story about when a data instance is for a type that looks like `T d`.
On the other hand, the user will be the one calling this method, and they'll have to take Data instances for d and use them to generate c (t d). Knowledge of if argument is of kind * is purely local, though. If t is Typeable and d is Data, then (t d), d is kind *, t :: * -> *. So to call dataCast1, the user has to already know the argument is kind *, and that the type t that they are trying to use (maybe not the T in the data instance itself) is of kind * -> *.
There is no contradiction in trying to call this on a data type with the wrong kind for it to succeed. T is not necessarily t. It is our job to check if it is.
Supplying the default shouldn't lock our data instance to the form T a. If for some reason adding this default would break the instance We can make a more interesting default that does something like look at the kind of the argument first to determine if it is kind * before proceeding after casting to ensure the kinds match.
tl;dr yes, it would seem it would be worth fixing the instances of Data produced to supply dataCast1 when the kind of the argument is polymorphic. Otherwise turning on PolyKinds in a package will simply break dataCast1 for basically all of its data types.
-Edward
P.S. Ultimately, in a perfect world we'd be able to unify dataCast1 and dataCast2 with some tricky base case for kind k1 = * and induction over k -> k1. Off hand, I don't see how to do it. I played for a while with trying to write a higher kinded Data to support this, but my scribbles didn't cohere into usable code. gfoldl pretty much locks you into kind *. I even tried playing with profunctors and powers here to no real avail. I do have some old Data1 code in an syb-extras package that I use to write a few 'impossible' Data instances, but that seems to be solving a different, if related, problem, and doesn't scale up to arbitrary kinds. Ideally there'd be a plausible Data that makes sense for other kinds k, and everything could become dataCast1, w/ dataCast2, and the missing higher versions just an iterated application of it. I just don't see that there is a way to turn it into code.
On Thu, Feb 23, 2017 at 2:51 PM, Ryan Scott
wrote: Hi Pedro,
I'm quite confused by a peculiarity of deriving Data (more info in Trac #13327 [1]). In particular, if you write this:
data T phantom = T deriving Data
Then the derived Data instance is NOT this:
instance Typeable phantom => Data (T phantom) where ...
But instead, it's this:
instance Data phantom => Data (T phantom) where ... dataCast1 f = gcast1 f
The gcast1 part is why it requires the stronger (Data phantom) context, as you noted in Trac #4028 [2].
What confuses me, however, is that is apparently does not carry over to poly-kinded datatypes. For instance, if you write this:
data T (phantom :: k) = T deriving Data
Then you do NOT get this instance:
instance Data (phantom :: *) => Data (T phantom) where ... dataCast1 f = gcast1 f
But instead, you get this instance!
instance (Typeable k, Typeable (phantom :: k)) => Data (T phantom) where ... -- No implementation for dataCast1
This is quite surprising to me. I'm not knowledgeable enough about Data to know for sure if this is an oversight, expected behavior, or something else, so I was hoping you (or someone else highly knowledgeable about SYB-style generic programming) could help me out here.
In particular:
1. Does emitting "dataCast1 f = gcast1 f" for datatypes of kind (k -> *) make sense? Or does it only make sense for types of kind (* -> *)? 2. Is there an alternate way to define dataCast1 that doesn't require the stronger Data context, but instead only requires the more general Typeable context?
Ryan S. ----- [1] https://ghc.haskell.org/trac/ghc/ticket/13327 [2] https://ghc.haskell.org/trac/ghc/ticket/4028#comment:5 _______________________________________________ ghc-devs mailing list ghc-devs@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/ghc-devs