Re: Use of forall as a sigil

I must be confused, because it sounds like you are contradicting yourself. :) In one sentence you say that there is no assumed universal quantification going on, and in the next you say that the function does indeed work for all types. Isn't that the definition of universal quantification? (We're definitely getting somewhere interesting!) Den tors 3 dec. 2020 17:56Richard Eisenberg skrev:

On Dec 3, 2020, at 10:23 AM, Bryan Richter wrote:

Consider `forall a -> a -> a`. There's still an implicit universal quantification that is assumed, right?

No, there isn't, and I think this is the central point of confusion. A function of type `forall a -> a -> a` does work for all types `a`. So I think the keyword is appropriate. The only difference is that we must state what `a` is explicitly. I thus respectfully disagree with

But somewhere, an author decided to reuse the same keyword to herald a type argument. It seems they stopped thinking about the meaning of the word itself, saw that it was syntactically in the right spot, and borrowed it to mean something else.

Does this help clarify? And if it does, is there a place you can direct us to where the point could be made more clearly? I think you're far from the only one who has tripped here.

Richard