Hi Adithya,
The representations are the same. You can do this. I do this somewhat
often. Just avoid mutating in places where it could result in funky stuffs.
This is usually pretty easy to spot.
Cheers,
chessai
On Mon, Jul 24, 2023, 12:59 Adithya Kumar
Hello all,
I have a use-case where I want to convert `ByteArray#` to `MutableByteArray#` without the copy overhead.
Is the underlying memory structure of `ByteArray#` and `MutableByteArray#` the same?
If I can guarantee that I won't mutate my `MutableByteArray#`, can I use `unsafeCoerce#` on `ByteArray#` and treat it as `MutableByteArray#`?
Best, Adithya _______________________________________________ ghc-devs mailing list ghc-devs@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/ghc-devs