
#14951: SpecContsr needs two runs when one should suffice -------------------------------------+------------------------------------- Reporter: nomeata | Owner: (none) Type: task | Status: new Priority: normal | Milestone: Component: Compiler | Version: 8.2.2 Keywords: SpecConstr | Operating System: Unknown/Multiple Architecture: | Type of failure: None/Unknown Unknown/Multiple | Test Case: | Blocked By: Blocking: | Related Tickets: #14844 Differential Rev(s): | Wiki Page: -------------------------------------+------------------------------------- This is a spin-off of #14844, which is a spin-off of #14068, but applies on its own. Consider this code: {{{ module T14844Example (topLvl) where topLvl large = (bar1, bar2, foo) where foo :: Integer -> (a -> b -> Bool) -> (a,b) -> Bool foo 0 _ _ = False foo s f t = l s' t where l 0 t = False l 1 t = case t of (x,y) -> f x y l n (x,y) = l (n-1) (x,y) s' = large s bar1 :: Integer -> (a -> b -> Bool) -> a -> b -> Bool bar1 s f x y = foo s f (x,y) bar2 :: Integer -> (a -> b -> Bool) -> a -> b -> Bool bar2 s f x y = foo (s + 1) f (x,y) }}} Status quo: `l` gets specialized, because of the two call patterns `s' t0` and `(s-1) (x,y)`, the second one is interesting *and* its second argument gets scrutinized (the `scu_occs` field reports `ScrutOcc` for `t`). But `foo` does not get specialized: It does have an interesting call pattern, but `scu_occs` reports `UnkOcc`, because `foo`’s parameters are just passed to `t`. But: When we decide to !SpecConstr `l`, we know that one of the calls to `l` is of the shape `s' t0`. This is a boring call, and we do not create a specialization for it. But we create a specialization for `l` using the the other call pattern. This means we know that it would be beneficial if `t0` were a constructor. So can we, at this point, decide to include `t0 ↦ ScrutOcc` in `scu_occs`? First experiments look good, so I am working on this. -- Ticket URL: http://ghc.haskell.org/trac/ghc/ticket/14951 GHC http://www.haskell.org/ghc/ The Glasgow Haskell Compiler