
#14694: Can't coerce given assumptions -------------------------------------+------------------------------------- Reporter: Iceland_jack | Owner: (none) Type: bug | Status: new Priority: normal | Milestone: Component: Compiler | Version: 8.2.2 Resolution: | Keywords: Roles Operating System: Unknown/Multiple | Architecture: | Unknown/Multiple Type of failure: None/Unknown | Test Case: Blocked By: | Blocking: Related Tickets: | Differential Rev(s): Wiki Page: | -------------------------------------+------------------------------------- Comment (by Iceland_jack): I don't remember a place where we collect them, we can make one & I can go through my old tickets in search for examples. Here is another one maybe: {{{#!hs {-# Language FlexibleContexts #-} import Data.Coerce class Exp repr where int :: Int -> repr Int newtype Coerce f a = Coerce (f a) -- /tmp/Test.hs:13:9: error: -- • Couldn't match representation of type ‘f Int’ with that of ‘Int’ -- arising from a use of ‘coerce’ -- • In the expression: coerce -- In an equation for ‘int’: int = coerce -- In the instance declaration for ‘Exp (Coerce f)’ -- • Relevant bindings include -- int :: Int -> Coerce f Int (bound at /tmp/Test.hs:13:3) -- | -- 13 | int = coerce -- | ^^^^^^ instance Coercible Int (f Int) => Exp (Coerce f) where int = coerce }}} but it works with `int = Coerce . coerce`. -- Ticket URL: http://ghc.haskell.org/trac/ghc/ticket/14694#comment:3 GHC http://www.haskell.org/ghc/ The Glasgow Haskell Compiler