Good evening,
OK. I don't know Haskell enough to argue.
But I can't resist pointing out that reading a single byte having the value 233
(that is 'é') is certainly simpler than reading the four characters "\233",
parse it, and translate it into a single byte having the value 233 representing
no matter what character in your character table.
But, I don't care that much and I'm sorry for this.
Best regards,
Francis Girard
LE CONQUET
France
Selon Carsten Schultz
Hallo!
On Thu, Dec 18, 2003 at 01:55:27PM +0100, francis.girard@free.fr wrote:
Well, I think there should probably be some internationalisation mechanism that tells the "show" function (to name one), according to some configuration, how to interpret a byte as a character.
My understanding is that `show' should work with `read' and possibly produce output that can be parsed by the Haskell parser. It is not a pretty printing function.
Frankly, I see no good reason why we should be satisfied we the dinosaurus 7 bits except perhaps because 7 bits is sufficient for english.
I am talking about respect for non english speaking people.
But if nobody cares ...
I, too, speak a language that can't be fully expressed in ASCII, but I do not think that the behaviour of `show' should be changed in this respect.
Greetings,
Carsten
-- Carsten Schultz (2:38, 33:47), FB Mathematik, FU Berlin http://carsten.fu-mathe-team.de/ PGP/GPG key on the pgp.net key servers, fingerprint on my home page.
Original message :
The following haskell program :
--<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<< module Main where
accentLetters :: String accentLetters = "éàô"
main :: IO () main = do putStr (show accentLetters) -->>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
after being compiled will give the result :
"\233\224\244"
But, exactly the same program, without the "show" function will give the result:
éàô
Is there some way to have "show" show all the printable characters, even those represented by a value greater than the US-ASCII 7 bits (127) ?