Re: Hiding module *exports*

El Oct 27, 2014, a las 9:57, Erik Hesselink escribió:

On Mon, Oct 27, 2014 at 2:41 PM, Daniel Trstenjak wrote:

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There's a little bit of bikeshedding that needs to happen (e.g. is "hiding (Foo (..))" sufficient to hide the type Foo and not just its constructors), but are people +1 on this? I've frequently wanted this behavior.

I would be surprised if 'Foo(..)' would mean in this case something different, so yes, the type Foo should be hidden too.

One related question: how would you export only the type if you have

newtype Foo = Foo ...

which is a pretty common pattern? Since "hiding (Foo(Foo))" would also hide the type, I don't see many options, which is unfortunate.

In general, I'm +1 on the proposal.

I'd say "hiding (Foo)" hides the type and constructor; "hiding (Foo(Foo))" hides only the constructor. Tom

Erik _______________________________________________ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users