Re: foldr f (head xs) xs is not the same as foldr1 f xs

Ah! thanks you're right, sorry. My problem arose from the fact that let x = 'A':undefined in head $ (unwords.words) x does not terminate, but now it's clear: For interspersing the blanks you need to evaluate the tail. Sorry again. Cheers, David Tomasz Zielonka schrieb:

On Sun, May 08, 2005 at 08:14:30PM +0200, David Sabel wrote:

...

Hi!

Subject: foldr f (head xs) xs is not the same as foldr1 f xs

I think you forgot about tail:

foldr f (head xs) (tail xs)

Best regards Tomasz _______________________________________________ Glasgow-haskell-users mailing list Glasgow-haskell-users@haskell.org http://www.haskell.org/mailman/listinfo/glasgow-haskell-users