Hi, Am Freitag, den 08.07.2016, 13:09 +0200 schrieb Sven Panne:
I don't think so: https://ghc.haskell.org/trac/ghc/wiki/ArgumentDo#Bl ockasaLHS explicit states that
do f &&& g x
parses as
(f &&& g) x
Correct
, so
foobar do f &&& g x
parses as
foobar ((f &&& g) x)
Where is the outer set of parenthesis coming from? This is all not related to the ArgumentDo notation. Note that (f &&& g) x parses as (f &&& g) x and still foobar (f &&& g) x parses as foobar (f &&& g) x just as foobar (f &&& g) x does. (NB: I consider foobar arg1 arg2 bad style and prefer foobar arg1 arg2 but the former is allowed now and will be allowed later as well.) Greetings, Joachim -- Joachim “nomeata” Breitner mail@joachim-breitner.de • https://www.joachim-breitner.de/ XMPP: nomeata@joachim-breitner.de • OpenPGP-Key: 0xF0FBF51F Debian Developer: nomeata@debian.org