On 18 January 2011 22:18, Johan Tibell
Why is the size in bytes?
I think the docs are wrong. The code for newArray# (in PrimOps.cmm) interprets n as a size in words: {{{ stg_newArrayzh { W_ words, n, init, arr, p, size; /* Args: R1 = words, R2 = initialisation value */ n = R1; MAYBE_GC(R2_PTR,stg_newArrayzh); // the mark area contains one byte for each 2^MUT_ARR_PTRS_CARD_BITS words // in the array, making sure we round up, and then rounding up to a whole // number of words. size = n + mutArrPtrsCardWords(n); words = BYTES_TO_WDS(SIZEOF_StgMutArrPtrs) + size; ("ptr" arr) = foreign "C" allocate(MyCapability() "ptr",words) [R2]; TICK_ALLOC_PRIM(SIZEOF_StgMutArrPtrs, WDS(n), 0); ... } }}} Cheers, Max