14 Feb
2005
14 Feb
'05
12:23 p.m.
Simon Marlow writes:
(#) :: a -> (a -> b) -> b a # f = f a
Haddock parses GHC extensions by default, so its syntax corresponds to GHC with -fglasgow-exts.
I see. Thanks for the clarification. Fortunately, writing ( # ) instead solves the problem. ;-) Peter