Re: [Haskell-cafe] "Wrong kind" when attempting to build a monad for a circular list of functions

I'm nitpicking but, On Thu, Feb 28, 2008 at 11:44 AM, Felipe Lessa wrote:

Bas van Dijk's 'always' (also called 'forever'[1])

forever a = a >> forever a always f z = f z >>= always f Forever doesn't pass the result of the action to its recursive call, always does.