[Haskell-cafe] Newbie question

Hi, I'm reading the Haskell school of expression by Paul Hudok. Great book. However I would like some feedback about a solution to an exercise The problem is quite simple : define f1 and f2 (using higher order functions ) such that f1 (f2 (*) [1..4]) 5 => [5,10,15,20] I have come up with the following solution : f2 :: (a->b)->[a] -> [b] f2 f xs = map f xs f1 fs a = map (applyOp a) fs applyOp b f = f b But I guess there must be some more elegant way. f2 isn't at all original. And the applyOp sounds silly. Any comments or suggestions are welcome. thanks, Pieter