Re: [Haskell-cafe] How to give unique name/id to nodes outside any monad ?

Great, System.Mem.StableName [1] seems to be able to do the trick. Thank you. [1] http://www.haskell.org/ghc/docs/latest/html/libraries/base/System-Mem-Stable... 2009/1/8 minh thu :

Well, the processing of the data structure has to be done in the IO monad. What is the library you talk about ? Could it give the "stable names" (in IO) for each node of the mentioned graph (I mean, after the graph has been constructed purely) ?

Thanks, Thu

2009/1/8 Lennart Augustsson :

...

Of course you don't need a monad, but you need to do the same operations as you would with a state monad to number the nodes. This is the only way in (pure) Haskell. There is no object identity in Haskell, so if you want the nodes to have identity you need to provide it.

GHC does have a library for stable names which (in the IO monad) allows you to get something akin to the address of a value in memory. But that's not the functional way of doing this.

-- Lennart

On Thu, Jan 8, 2009 at 9:28 AM, minh thu wrote:

...

Hi,

I'd like to process some kind of graph data structure, say something like

data DS = A [DS] | B DS DS | C.

but I want to be able to discover any sharing. Thus, in

b = B a a where a = A [C],

if I want to malloc a similar data structure, I have to handle to the node representing B two times the same pointer (the one returned after allocating A [C]).

To discover sharing, I thought it would be necessary to give unique name to node and then compare them while traversing the graph. I could give the name by hand but it would be cumbersome. But at least it would not require any monad for the bookkeeping of ungiven names. Is it possible to give those names automatically but outside any monad ?

Thanks, Thu _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe