Re: [Haskell-cafe] How to get a file path to the program invoked?

1 Dec 2011

      On 01.12.2011 23:47, dokondr wrote:
...
To be precise, $0 always contains the path to the program called. You
are right, this path will change depending on location from which the
program was called. So $0 is OK for my case, while current directory  is
unrelated.
Actually it contains whatever was passed to exec. By convention this is 
program name but it could be anything

#include 
#include 

int main(int argc, char** argv)
{
     if( argc != 1 ) {
         printf("%i: %s\n", argc, argv[0] );
     } else {
         execl("./argv","Random junk","",0);
     }
     return 0;
}

$ gcc argv.c -o argv && ./argv
2: Random junk
...
Try this:
#!/bin/sh
echo "Arg 0: $0"
echo "All Parameters:  [$@]"
Again, any way to get the same functionality in GHC?
getArgs and getProgName should do the trick

http://hackage.haskell.org/packages/archive/base/latest/doc/html/System-Envi...

Re: [Haskell-cafe] How to get a file path to the program invoked?

Alexey Khudyakov