Re: [Haskell-cafe] GHC RTS question

Am Sonntag 21 Februar 2010 19:58:12 schrieb Artyom Kazak:

2010/2/21 Daniel Fischer :

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Am Sonntag 21 Februar 2010 18:20:43 schrieb Artyom Kazak:

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Enclose it in double quotes (perhaps single quotes would also work)

No, I want my program to work the same way as UNIX "echo" does. Without any double quotes.

Okay, what about

"If you absolutely positively want all the rest of the options in a command line to go to the program (and not the RTS), use a ––RTS."

$ ./prog +RTS --RTS +RTS

? (BTW, enclosing in quotes doesn't work anyway if the argument consists *only* of "+RTS", same as with echo, echo "-e" doesn't output '-e' either).

So, if I type "./prog +RTS --RTS +RTS", the output will be "+RTS". But I want the output to be equal to the input IN ALL CASES, without any quotes, additional options, etc. I want all the command line to go to my program. How can I do it? (The only way I know now - hacking the GHC. If there are no other ways, I'll do it.)

Shell wrapper: $ cat wopTest ./opTest +RTS --RTS $@ $ cat opTest.hs module Main (main) where import System.Environment (getArgs) main = mapM_ print =<< getArgs $ ./wopTest +RTS -sstderr -RTS "+RTS" "-sstderr" "-RTS" Other than that, hacking GHC is the only way I can think of either, since looking for RTS-options is a fixed (and generally necessary) part of the RTS. But why do you want that behaviour so much that you'd be willing to hack GHC?