Re: [Haskell-cafe] Removing alternate items from a list

alts :: [a] -> [a] alts xs = map fst . filter snd $ zip xs (cycle [False, True]) Prelude> alts [0, 1..5] [1,3, 5] On Sunday Jun 6, 2010, at 10:46 AM, R J wrote:

What's the cleanest definition for a function f :: [a] -> [a] that takes a list and returns the same list, with alternate items removed? e.g., f [0, 1, 2, 3, 4, 5] = [1,3,5]?

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