Kim-Ee Yeoh said: On the same note, does anyone have ideas for the following snippet? Tried the pointfree package but the output was useless.
pointwise op (x0,y0) (x1,y1) = (x0 `op` x1, y0 `op` y1)
First sorry for the delay in getting to this.. been behind on projects so had some days of mail piled up. Here is what I came up with, using one arrow operator, so you would have to import: Control.Arrow ((***)) at minimum to use this solution: pointfree :: forall t t1 c. (t -> t1 -> c) -> (t, t1) -> (t, t1) -> (c, c) pointfree op = curry $ (\(a,b) -> a `op` b) *** (\(a,b) -> a `op` b) examples of use, that were executed using: ghci -fglasgow-exts -farrows Control.Arrow *>pointfree (*) (3,5) (12,12) (15,144) *> pointfree (++) ("This ","That") ("Old"," Man") ("This That","Old Man") Hope that helps. -- gene ============================== website: http://haskblog.cloud.prohosting.com ============================== If Helen Keller is alone in a forest and falls, does she make a sound? ____________________________________________________________ Receive Notifications of Incoming Messages Easily monitor multiple email accounts & access them with a click. Visit http://www.inbox.com/notifier and check it out!