foldr

Hi all, If I have a function: it f [a0, a1, a2, ...] = [a0, f a1, f (f a2), ...] Is there any way of expressing it f as an instance of foldr? Many thanks, Jim ________________________________________________________________________ Yahoo! Messenger - Communicate instantly..."Ping" your friends today! Download Messenger Now http://uk.messenger.yahoo.com/download/index.html