Re: [Haskell-cafe] Re: Reversing a string of words: C# v Perl V Ruby v Haskell

ulfn:

On Dec 13, 2006, at 3:54 AM, Yitz Gale wrote:

...

Nice. Here is something similar:

reverseWords = concat . reverse . groupBy eqsp where eqsp x y = isSpace x == isSpace y

This can be made even nicer using the 'on' function [1]:

reverseWords = concat . reverse . groupBy ((==) `on` isSpace)

[1] http://www.haskell.org/pipermail/libraries/2006-November/006156.html

Lambdabot trick(tm), use 'join' in the [] monad, instead of 'concat' join . reverse . groupBy ((==) `on` isSpace) -- Don