Re: [Haskell-cafe] How to get a file path to the program invoked?

1 Dec 2011

      To be precise, $0 always contains the path to the program called. You are
right, this path will change depending on location from which the program
was called. So $0 is OK for my case, while current directory  is unrelated.

Try this:

#!/bin/sh

echo "Arg 0: $0"
echo "All Parameters:  [$@]"

Again, any way to get the same functionality in GHC?

On Thu, Dec 1, 2011 at 10:32 PM, Giovanni Tirloni wrote:
...
On Thu, Dec 1, 2011 at 5:26 PM, dokondr  wrote:
...
On the contrary, standard shell variable $0 - contains a full path to the
program location in the directory structure, no matter from what directory
the program was called.
Are you sure?
$ zero.sh
./zero.sh
$ ./zero.sh
./zero.sh
$ /home/gtirloni/zero.sh
/home/gtirloni/zero.sh
--
Giovanni