
20 Sep
2010
20 Sep
'10
7:12 p.m.
On Mon, Sep 20, 2010 at 5:11 PM, Luke Palmer
On Sun, Sep 19, 2010 at 5:01 PM, Henrique Becker
wrote: Why not?
import Data.Number.Nat as N
lastN :: Integral b => b -> [a] -> [a] lastN n xs = N.drop (N.length xs - n') xs where n' = N.toNat n
Wow. That is gorgeous! I think it's basically the same idea as my "zipWith" implementation, but it is so much clearer here. Thanks :-)
Er forget that zipWith comment. It is quite unlike that. But it is still beautiful and efficient.