22 Jul
2013
22 Jul
'13
9:55 a.m.
in this case, neither of them is memoized. because they don't have any data
in expressions.
"memoized" is for constants who have data structure in its expression
2013/7/22 Tom Ellis
On Mon, Jul 22, 2013 at 07:52:06PM +1200, Chris Wong wrote:
A binding is memoized if, ignoring everything after the equals sign, it looks like a constant.
In other words, these are memoized: [...] f = \x -> x + 1 [...] and these are not:
f x = x + 1
In what sense is the former memoised? I'm not aware of any difference between these two definitions.
Tom
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