Re: [Haskell-cafe] Dividing integers?

"Matias Hernandez" writes:

I mean, apparently "/" is not defined for integers but I don't know how to "cast" the result of the length function into a Double...

Prelude> (length [1,2]) / 3

Prelude> fromIntegral (length [1,2])/3 0.666666666666667

Prelude> 2 / 3 0.6666666666666666

Literal 2 means fromIntegral 2, but length::[a]->Int. -- Feri.