Re: [Haskell-cafe] Map list of functions over a single argument

On 20/02/07, Donald Bruce Stewart wrote:

p.f.moore:

...

I'm after a function, sort of equivalent to map, but rather than mapping a function over a list of arguments, I want to map a list of functions over the same argument. The signature would be [a -> b] -> a -> [b], but hoogle didn't come up with anything.

Prelude> map ($ 3) [(*2),(+1),div 1] [6,4,0]

Cool. I told you I was missing something! :-) The more I learn about using higher order functions, the more impressed I get. Thanks, Paul