I'm not happy with any of these options.
Why are you unhappy with the ImplicitParams option?
It's pretty much like resorting to a newtype, as it's been suggested before.
2012/6/27 Tillmann Rendel
Hi Rico,
Rico Moorman wrote:
data Tree = Leaf Integer | Branch (Tree Integer) (Tree Integer)
amount:: Tree -> Integer amount (Leaf x) = x amount (Branch t1 t2) = amountt1 + amountt2
[...] additional requirement: "If the command-line flag --multiply is set,
the function amount computes the product instead of the sum."
How would you implement this requirement in Haskell without changing the line "amount (Leaf x) = x"?
The (for me at least) most obvious way to do this would be, to make the
operation to be applied to determine the amount (+ or *) an explicit parameter in the function's definition.
data Tree a = Leaf a | Branch (Tree a) (Tree a) amount :: (a -> a -> a) -> Tree a -> a amount fun (Leaf x) = x amount fun (Branch t1 t2) = amount fun t1 `fun` amount fun t2
I agree: This is the most obvious way, and also a very good way. I would probably do it like this.
Which drawbacks do you see besides increased verbosity?
Well, you did change the equation "amount (Leaf x) = x" to "amount fun (Leaf x) = x". In a larger example, this means that you need to change many lines of many functions, just to get the the value of fun from the point where it is known to the point where you need it.
[...] I am wondering which ways of doing this in Haskell you mean.
I thought of the following three options, but see also Nathan Howells email for another alternative (that is related to my option (1) below):
(1) Implicit parameters:
{-# LANGUAGE ImplicitParams #-} data Tree = Leaf Integer | Branch Tree Tree
amount :: (?fun :: Integer -> Integer -> Integer) => Tree -> Integer
amount (Leaf x) = x amount (Branch t1 t2) = ?fun (amount t1) (amount t2)
(2) Lexical Scoping:
data Tree = Leaf Integer | Branch Tree Tree
amount :: (Integer -> Integer -> Integer) -> Tree -> Integer amount fun = amount where {
amount (Leaf x) = x ; amount (Branch t1 t2) = fun (amount t1) (amount t2) }
(3) UnsafePerformIO:
import System.IO.Unsafe (unsafePerformIO)
data Tree = Leaf Integer | Branch Tree Tree
amount :: Tree -> Integer amount (Leaf x) = x amount (Branch t1 t2) = fun (amount t1) (amount t2) where fun = unsafePerformIO ...
I'm not happy with any of these options. Personally, I would probably go ahead and transform the whole program just to get the value of fun to where it is needed. Nevertheless, having actually done this before, I understand why Martin Odersky doesn't like doing it :)
Tillmann
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